Question

Mrs. Reid is going on a trip. She has 9 books that she hasn't read yet, but she wants to bring only 3 on the trip. In how many ways can she choose 3 books to bring on the trip?
♦27
♦84
♦504
♦60,480

Answer 1

I am positive it is 27. Really you just have to read carefully. 9 books and she wants to bring 3 only You cant add it thats dumb.


Cant Subtract because your answer wouldn't even be the options.

Dividing, the answer would be 3 so no


Multiplication is apprentely the way to go.


9 times 3 is 27


Answer is A.


I may be wrong but thats what I got


Brainliest if satisfied


Would help a lot!

Answer 2

Answer:

Option B is right.

Step-by-step explanation:

Given that there are totally 9 books unread by Mrs. Reid.  OUt of these she wants to take only 3 books on the trip.

For books order does not count.

Hence combinations would be appropriate to calculate.

3 books out of 9 can be selected in

9C 3 ways

No of ways of selecting 3 books for the trip out of 9 = $\frac{9(8)(7)}{1(2)(3)} =84$

There are just 84 ways of choosing 3 books to bring on the trip out of 9 unread books.

Option B is right.