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shusha [124]
3 years ago
13

6/9 written two different ways

Mathematics
1 answer:
Rashid [163]3 years ago
5 0
6/9 is equivalent to the fractions 60/90 and 600/900. The amount of zeros you add on does not matter as long as you do it to the top and bottom. The division sign cancels it out.
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Hospitals typically require backup generators to provide electricity in the event of a power outage. Assume that emergency backu
JulsSmile [24]

Answer:

a) There is a 10.24% probability that both generators fail during a power outage.

b) There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

Step-by-step explanation:

For each emergency backup generator, there are only two possible outcomes. Either they work correctly, or they fail. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Assume that emergency backup generators fail 32% of the times when they are needed. So they work correctly 100-32 = 68% of the time. So p = 0.68

There are two generators, so n = 2

a. Find the probability that both generators fail during a power outage

This is P(X = 0)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.68)^{0}.(0.32)^{2} = 0.1024

There is a 10.24% probability that both generators fail during a power outage.

b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital? Assume the hospital needs both generators to fail less than 1% of the time when needed.

Either there are no working generators, or there is at least one working generator. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1024 = 0.8976

There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

To be high enough for the hospital, this probability should be at least of 99%.

7 0
3 years ago
A science teacher has 0.4 liter of seawater .She gives each of her 22 students a container and a 5-millimeter spoon. She their a
creativ13 [48]
"her students to put two spoonfuls of seawater into their containers"
 We have then:
 (2) * (5) = 10 mililiter
 "he gives each of her 22 students a container"
 Thus,
 (22) * (10) = 220 mililiter
 Therefore, they will remain:
 (0.4 * 1000) - 220 = 400 - 220 = 180 milliliter
 Answer:
 
There will be left 180 mililiter of seawater after all 22 students have filled their containers
7 0
3 years ago
CAN SOMEONE PLEASE HELP ME???
KATRIN_1 [288]

Answer:

Option A, x ≥ -2

Step-by-step explanation:

<u>Since the line is not dotted, that means that -2 is included.  Also, since the darkened part is toward positive infinity, that means that it is ≥.</u>

<u />

So, it is <em>x ≥ -2</em>

Answer:  Option A, x ≥ -2

5 0
3 years ago
Find the values of x and y for which the lines are parallel.
prisoha [69]
This problem is accompanied by a figure.

You can infere these relationships from the figure

(x-5)° = 74° => x = 74 + 5 = 79°

(x-5)° + 58° + (y-1)° = 180 ° => 74 + 58 + y-1 = 180 =>

y = 180 + 1 - 58 - 74 = 47°

Answer: x = 79°, y = 47°. This is the option d)


5 0
3 years ago
Help me and thx alot
Svet_ta [14]

Answer:

easyyyyyyy

Step-by-step explanation:

table J!

8 0
3 years ago
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