Help pls !!!!!!!brainliest goes to first right answer
1 answer:
Hi there!
To solve, we can divide the figure into a rectangle and triangle:
The rectangle has dimensions 20in and 30in. The formula A = l × w will be used to find the area.
The triangle has dimensions 40 (10 + 20 + 10) in and 30 in. The formula A = 1/2(b· h) can be used to find the area.
Find the area of each shape:
A = 20 × 30 = 600in²
A = 1/2(40 × 30) = 600in²
Find the sum of both to find the area of the total figure:
600 + 600 = 1200in²
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3:5 ratio mean there are 8 "parts" (3 + 5 = 8)
The distance between the x-coordinates is |-3 - 5| = 8.
So each "part" is 8/8 = 1 unit long in the x-direction.
You want I to be 3(1) = 3 units from D, so the x-coordinate of I is -3 + 3 = 0.
Same deal for y.
|2 - 5| = 3 is the distance between D and E
Each part is 3/8.
3(3/8) = 9/8
2 + 9/8 = 25/8
So the point I is (0, 25/8)
The distance between the x-coordinates is |-3 - 5| = 8.
So each "part" is 8/8 = 1 unit long in the x-direction.
You want I to be 3(1) = 3 units from D, so the x-coordinate of I is -3 + 3 = 0.
Same deal for y.
|2 - 5| = 3 is the distance between D and E
Each part is 3/8.
3(3/8) = 9/8
2 + 9/8 = 25/8
So the point I is (0, 25/8)