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3 years ago

Robert came in first for 3/4 of his race. Express this fraction as a decimal

1 answer:

4 0

SOLUTION:

= 3 / 4

= 75 / 100

= 0.75

Therefore, Robert came in first for 0.75 of his race.

Hope this helps. :)
Have a lovely day! <3

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the distance from Earth to the Sun is approximately 93 million miles about how many gigameters is this...Round to nearest hundre

Ivahew [28]

.093

So .09
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3 years ago

Find the slope of the line that passes through (-24, 90) and (-23, 52).

Ostrovityanka [42]

Answer:

-38

Step-by-step explanation:

The slope is rise over run. You need to find out how far one point is from the other. To do this, use the equation for slope.

$m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }$

Plug in the points given into the equation and solve for slope (m).

$m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }\\m=\frac{90-52 }{-24-(-23) }\\m=\frac{90-52 }{-24+23 }\\m=\frac{38}{-1} \\m=-38$

The slope of the line is -38.

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3 years ago

Can somebody help me out please !

ivann1987 [24]

Answer:

d i think maybe i dont know if im rong ask some one else

5 0

3 years ago

if the probability of picking a green marble from a bag of green and red marbles is 0.3. if i choose a marble 100 times and repl

vfiekz [6]

Answer:

30 marbles would be green

Step-by-step explanation:

green chance is 0.3

red chance 0.7

.3 times 100

30 green marbles is what you would expect

7 0

3 years ago

Suppose 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at

ANEK [815]

Answer:

We conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

Step-by-step explanation:

We are given that 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at a fourth grade level.

Further suppose 135 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not "do math" at a fourth grade level (like fractions).

Let $p_1$ = proportion of college students who would be embarrassed to truthfully admit they could not read at a fourth grade level.

$p_2$ = proportion of college students who would be embarrassed to truthfully admit they could not "do math" at a fourth grade level.

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 or $p_1= p_2$ {means that there is not any significant difference in the proportion of all college students who would be embarrassed by these two admissions}

Alternate Hypothesis, $H_A$ : $p_1-p_2$ $\neq$ 0 or $p_1\neq p_2$ {means that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions}

The test statistics that would be used here Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of college students who would be embarrassed to admit they could not read at a fourth grade level = $\frac{462}{500}$ = 0.924

$\hat p_2$ = sample proportion of college students who would be embarrassed to admit they could not "do math" at a fourth grade level = $\frac{135}{500}$ = 0.27

$n_1$ = sample of college students = 500

$n_2$ = sample of college students = 500

So, test statistics = $\frac{(0.924-0.27)-(0)}{\sqrt{\frac{0.924(1-0.924)}{500}+\frac{0.27(1-0.27)}{500} } }$

= 28.28

The value of z test statistics is 28.28.

Also, P-value of the test statistics is given by;

P-value = P(Z > 28.28) = Less than 0.0005%

Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

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4 years ago