Question

A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.

Answer 1

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

              $\texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}$

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

$\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2$

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²