Which expression has the smallest value a -19 -34 22 47

Mathematics

1 answer:

timurjin [86]2 years ago

4 0

-34 because it's a negative number and it's smaller than -19

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What is the slope of (-1,6) and (2,3)?

LenKa [72]

Answer:

-1

Step-by-step explanation:

For a line joining two points (x1, y1) and (x2, y2), it's slope is given as:

$\boxed{ \mathsf{slope = \frac{ y_{2} -y _{1}}{ x_{2} - x _{1}} }}$

Here, the two points are (-1, 6) and (2, 3) in place of (x1, y1) and (x2, y2).

Solving for slope:

$\implies \mathsf{ \frac{3 - 6}{2 - ( -1 )} }$

$\implies \mathsf{ \frac{ - 3}{2 + 1 } }$

$\implies \mathsf{ \frac{ - 3}{3 } }$

$\implies \mathsf{ - 1 }$

Hence, the slope of the line joining the given points is -1.

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2 years ago

Lisa draws a circle by tracing around the bottom of block. which could be the shape of Lisa's block

Andrej [43]

Let's think of something that one can hold against a page and draw a circle. Some examples are: a cup, a D battery, a can of soda, the tube from the inside of a paper towel roll, a can of beans, etc.

Think of the can of beans. The part that touches the page (and that you trace around with your pencil) is called a face.What these items have in common is that the faces at the ends are circles (they may or may not be the same size).

The name for this 3-D figure is called a cylinder. Her block, therefore, is a cylinder.

Technically, if the ends were ovals we would still call it a cylinder and so to make sure you have the one with the circles at the ends you would say you have a "right circular cylinder" but for most cases people just say "cylinder" and assume the ends are circles. It really depends what level (elementary, middle school, hs, college) of math you are doing whether just cylinder suffices.

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2 years ago

What is the word form for this mixed number? 11 3/8

Zanzabum

Answer:

Just getting my points back don’t mind me

Step-by-step explanation:

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2 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$