What is the equation of the line, written in slope-intercept form? Show how you determined the equation.

Mathematics

1 answer:

kondor19780726 [428]3 years ago

4 0

The equation of a line is defined by: y=mx+b

Step 1: Find the slope (rise over run) so, the rise is 15.7 and the run is 6. 15.7/6=2.62

y=2.62x+b

Step 2: Find the b value (y intercept) - this is where the line goes through the y axis. In this case, it's 15.7

Step 3: add the slope and the b value together - y=2.62x+15.7

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What is the measure of AngleDCF? Three lines extend from point C. The space between line C D and C E is 75 degrees. The space be

gizmo_the_mogwai [7]

Answer:

∠DCF = 129°

Step-by-step explanation:

We assume that line CE is between lines CD and CF.

The angle sum theorem applies:

∠DCF = ∠DCE +∠ECF

∠DCF = 75° +54°

∠DCF = 129°

4 0

4 years ago

Read 2 more answers

1.Simplify 5 to the 5th over 5 to the 8th.

timurjin [86]

Q1. The answer is 1 over 5 to the 3rd power.

5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is $\frac{ 5^{5} }{ 5^{8} }$
To simplify, we will use two rules:
$\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}$
Therefore:
$\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}$
$\frac{1}{5^{3}}$ is the same as 1 over 5 to the 3rd power.

Q2. The answer is (53)−4.

The exponents are multiplied when are expressed in the form:
 $(x^{a}) ^{b}= x^{a*b}$
So, $(5^{3} )^{-4}=5^{3*(-4)}=5^{-12}$

Other choices are incorrect:
one third to the 4th times one third to the 7th is $( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}$
3 to the 7th over 3 to the 15th is $\frac{ 3^{7} }{3^{15}} =3^{7-15}$
45 ⋅ 42 is $4^{5}* 4^{2} = 4^{5+2}$