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Hoochie [10]
3 years ago
10

I NEED HELP(10 POINTS) ON THIS PROBLEM

Mathematics
1 answer:
agasfer [191]3 years ago
8 0
(1250-140)/2

1110/2

answer= 550

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Represent the following algebraically. A number, x, decreased by the sum of 2x and 5
sashaice [31]
The answer is x-(2x+5) 
8 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
Write an equation in standard form of the hyperbola described.
marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

5 0
2 years ago
caley is making some punch for her birthday party.She mixes 1/2 litre of cranberry juice,1/1/2 litres of apple juice,2/3 litre o
vlabodo [156]

Answer:

yes it will contain it  

Step-by-step explanation:

.5 + 1.5 + .66 + .8 = 3.46

7 0
3 years ago
Daine simplified the expression below.
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

8(1 + 2i) -  (7 - 3i) = 8*1 + 8*2i + 7*(-1) - 3i*(-1)

                          = 8 + 16i -7 + 3i

                          = 8 - 7 + 16i + 3i

                          = 1 + 19i

Daniel forgot to multiply 2i by 8

3 0
3 years ago
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