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3 years ago

15

Find the missing terms of the geometric sequence.

1 answer:

Debora [2.8K]3 years ago

6 0

Funny cause I just did something similar a few minutes ago

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In January. The temperature in Fargo, North Dakota is -2 F. On the same day, the temperature in Cheyenne, Wyoming was 1 F. Write

zaharov [31]

Answer:

(a) $1 > -2$ or $-2 < 1$

(b) $2 > 1$ or $1 < 2$

Step-by-step explanation:

Given

$N = -2F$ --- North Dakota

$C = 1F$ --- Cheyenne, Wyoming

Solving (a): Inequality to compare both temperatures

From the given temperatures, we can conclude that:

$C > N$ or $N < C$

Because

$1 > -2$ i.e. 1 is greater than -2

or

$-2 < 1$ i.e. -2 is less than 1

Solving (b): Inequality to compare the absolute values of the temperatures

We have:

$N = -2F$

$C = 1F$

The absolute values are:

$|N| = |-2|$

$|N| =2$

$|C| = |1|$

$|C| = 1$

By comparison:

$|N| > |C|$ or $|C| < |N|$

Because

$2 > 1$ i.e. 2 is greater than 1

or

$1 < 2$ i.e. 1 is less than 2

4 0

3 years ago

Prove that the two circles shown below are similar.

Setler [38]

Answer:

The scale factor is $\frac{R_{A}}{R_{C}}=\frac{5}{2}$

<u>We can say that both circles are similar.</u>

Step-by-step explanation:

If we move the little circle to the center of the bigger circle, so the <u>translate vector will be (3,5).</u>

Now we realize that the bigger circle is just a dilation of the smaller circle, the<u> scale factor is:</u>

$R_{A}=5$

$R_{C}=2$

$\frac{R_{A}}{R_{C}}=\frac{5}{2}$

Therefore, <u>we can say that both circles are similiar.</u>

<u />

I hope it helps you!

8 0

3 years ago

A: There there are two pencils boxes in a desk for their own purposes in a drawer then total number of pencils in the drawer is

Damm [24]

Answer:

C

Step-by-step explanation:

I got it right

8 0

3 years ago

Which two values of x are roots of the polynomial below?<br> 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

so

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

so

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

6 0

3 years ago

Please help me <br>and please show good answers

MaRussiya [10]

Answer:

1st one is 0.021

2nd one is 0.009

the last question is 0.015 tho

6 0

2 years ago

Read 2 more answers