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shepuryov [24]
3 years ago
8

Prove that the two circles shown below are similar. ​

Mathematics
1 answer:
Setler [38]3 years ago
8 0

Answer:

The scale factor is \frac{R_{A}}{R_{C}}=\frac{5}{2}

<u>We can say that both circles are similar.</u>

Step-by-step explanation:

If we move the little circle to the center of the bigger circle, so the <u>translate vector will be (3,5).</u>

Now we realize that the bigger circle is just a dilation of the smaller circle, the<u> scale factor is:</u>

R_{A}=5

R_{C}=2

\frac{R_{A}}{R_{C}}=\frac{5}{2}

Therefore, <u>we can say that both circles are similiar.</u>

<u />

I hope it helps you!

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the area of a window is 192 in squared. The width if the window is four inches more than half the length of the window. What are
Leya [2.2K]

Answer:

Length = 16 inches and width = 12inches

Step-by-step explanation:

A = 192 in² . The width is 4 + 1/2x.  therefore let x = length

Area = LW

192 =  x(4 + 1/2 x)

192 = 4x + 1/2x²      

384 = 8x  + x²                            Multiply each term by 2 to make a  

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400 = (x  + 4)²        

\sqrt{400} = \sqrt{(x + 4)^2}

± 20 = x + 4

20 = x + 4  or  -20 = x + 4

20 - 4 = x     or  -20 - 4 = x

    16 = x   or   -24 = x   reject the negative amount

   Length = 16

   width = 4 + 1/2(16);   4 + 8 = 12

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2 years ago
Three improper fractions for 4 1/2
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7 0
3 years ago
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$46 shoes; 2.9% tax what is the answer?
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Solve: 5x(8-4) divide 4-2=
nataly862011 [7]

5x(8 - 4)/4 - 2

Remember to follow PEMDAS.

First, subtract 8 and 4

8 - 4 = 4

5x(4)/4 - 2

Next, follow the left -> right rule, and multiply 5x and 4

5x(4) = 20x

Divide by 4

20x/4 = 5x

Finally, note that one has a variable, and the other has a constant, and so you cannot combine.

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8 0
3 years ago
Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

\frac{sin30}{4}=\frac{sinB}{6}

sinB=0.75

angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

\frac{sinA}{a}=\frac{sinC}{c}

\frac{sin30}{4}=\frac{sin101.4}{c}

c = 7.84

Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

\frac{sin30}{4}=\frac{sin18.6}{c'}

c'=2.55

Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0
3 years ago
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