Answer:
Step-by-step explanation:
(-6 , 4) & (-1 , 2)
Slope = 
![= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B2-4%7D%7B-1-%5B-6%5D%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B-1%2B6%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B5%7D)
m = -2/5 & (-6 , 4)
y -y1 = m(x -x1)
![y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}](https://tex.z-dn.net/?f=y%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20%2B%206%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20%2B%206%2A%5Cfrac%7B-2%7D%7B5%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20-%5Cfrac%7B12%7D%7B5%7D%2B4%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B4%2A5%7D%7B1%2A5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B20%7D%7B5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx%2B%5Cfrac%7B8%7D%7B5%7D)
Answer:
15 5/8 ft^3
Step-by-step explanation:
Volume of a cube = l x b x h
Given the Length of sides is
2 1/2
Change 2 1/2 to an improper fraction.
It becomes 5/2
Volume = 5/2 x 5/2 x 5/2
Multiply through
= 125/8
= 15 5/8 ft^3
Answer:
y intercept (0, 4)
x intercept (4, 0)
I hope this is good enough:
When the rocket accelerates up, the thrust is greater than the combined lift and drag, therefore making it go upward. Thrust from the engine / or whatever the power source is makes it lift.
Hope that helps!
Solve for y and then graph it on a graphing calculator or since it doesn’t have a exponent you know it’s just a line because it would be the like y=4 which is a horizontal line at 4