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bezimeni [28]
2 years ago
15

Find b. Round to the nearest tenth.

Mathematics
2 answers:
Svetradugi [14.3K]2 years ago
5 0
Find Angle B:  B = 180 - (82+55) = 43.  Then apply the law of sines:

   b            8 cm
--------- = ----------
sin 43       sin 55
                                        (sin 43)(8 cm)
Solving for b, we get b = ------------------- = 6.66, or 6.7 (cm, to the nearest tenth).     
                                              sin 55
vlabodo [156]2 years ago
3 0
This is 90 degrees because we have to have an right angle and a right angle is 90 degrees
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Help me on 5 and 6 please
ankoles [38]

Answer:

THE PICTURE IS BLURRY

Step-by-step explanation:

ITS PROBABLY BC I DONT HAVE AN IPHONE LOLOLOLOLOLOLOLOLOL

7 0
2 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
What is the solution to the equation and explain your reasoning ​
Sergeu [11.5K]

Answer:

I think x = 1.5

Step-by-step explanation:

23 - 17 = 6

6 ÷ 4 = 1.5

5 0
2 years ago
Amber has some state quarters in her pocket. She collects the following data by randomly pulling one quarter recordings the stat
ch4aika [34]
To do this problem, we need one more piece of information. He need to know the percent of the quarters that are from New York.

If you had that number, just multiply it by 300.

For example, if 10% of the coins were from New York, just multiply by 0.1.
0.1 x 300 = 30
4 0
3 years ago
What is the value of the expression |a + b| + |c| when a = –6, b = 2, and c = –11?
nika2105 [10]
|-6 + 2| + |-11| 

|4| + |-11|

= 15

Hope i helped! 
3 0
3 years ago
Read 2 more answers
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