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nexus9112 [7]
2 years ago
9

Two buses leave towns 1015 miles apart at the same time and travel toward each other. One bus travels 11 miles/hr slower than th

e other. If they meet in 7 hours, what is the rate of each bus?
Mathematics
1 answer:
kiruha [24]2 years ago
3 0

Answer:

Step-by-step explanation:

Bus One

speed = x

t = 7 hours

d = ?

Bus two

speed = x + 11

time = 7 hours

d1 = 1015 miles - d

Equations

d = s * t

Bus 1 + bus 2 = 1015

Solution

x * 7 + (x + 11)*7 = 1015

7x + 7x + 11*7 = 1015

14x + 77  =1015

14x + 77 - 77 = 1015 -  77

14x = 938

14x/14 = 938/14

x = 67 miles / hour

x + 11 = 78 miles / hour

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Find the angle measures. Justify your responses.
MatroZZZ [7]

Answer:

m∠3 = 2x - 10° and m∠6 = 3x + 20

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a ║ b

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m∠7 = m∠3                   If ║ cut by a transversal, then corresponding angles

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m∠2 = 3x + 20              Given

m∠7 = 2x - 10                 Given    

m∠6 + m∠3 = 180°         If ║ cut by a transversal, then each pair of same-side

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