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nexus9112 [7]
3 years ago
9

Two buses leave towns 1015 miles apart at the same time and travel toward each other. One bus travels 11 miles/hr slower than th

e other. If they meet in 7 hours, what is the rate of each bus?
Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Answer:

Step-by-step explanation:

Bus One

speed = x

t = 7 hours

d = ?

Bus two

speed = x + 11

time = 7 hours

d1 = 1015 miles - d

Equations

d = s * t

Bus 1 + bus 2 = 1015

Solution

x * 7 + (x + 11)*7 = 1015

7x + 7x + 11*7 = 1015

14x + 77  =1015

14x + 77 - 77 = 1015 -  77

14x = 938

14x/14 = 938/14

x = 67 miles / hour

x + 11 = 78 miles / hour

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Answer:

x=2 and y=8

Step-by-step explanation:

Given:

Equation 1:

500y-600x=2800

Simplifying the above equation by dividing both sides by 100

\frac{500y-600x}{100}=\frac{2800}{100}

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Equation 2:

400y-400x=2400

Simplifying the above equation by dividing both sides by 400.

\frac{400y-400x}{400}=\frac{2400}{400}

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Now the system of equation is:

(1a) 5y-6x=28

(2a) y-x=6

Solving by elimination

Multiplying equation (2a) with -5

-5(y-x)=-5\times 6

(2b) -5y+5x=-30

Adding equations (1a) and (2b) in order to eliminate y

      5y-6x=28

+  -5y+5x=-30

We get -x=-2

∴ x=2

Plugging x=2 in equation (2a).

y-2=6

Adding 2 both sides.

y-2+2=6+2

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Step-by-step explanation:

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Mouse- M , Cat - C, Dog - D

M + C = 10 ----- (1)

M + D = 20 -------(2)

C + D = 24 --------(3)

(1) - (2) => C - D = -10 ---- (4)

(3) + (4) => 2C = 14

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Substitute C in (1)  => M + 7 = 10

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Substitute M in (2) => 3 + D = 20

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3 0
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Answer:

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