Let x = number of students in each of the remaining rows
266 = (10 x 20) + (5 x 8) + 2x
266 - (10 x 20) - (5 x 8) = 2x
266 - 200 - 40 = 2x
26 = 2x
x = 26/2
x = 13
7 + 28n + 4
28n + (7 + 4)
28n + 11
First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Hey there! I was looking at your question for a bit then realized you meant 
, the imaginary number, not "1" at the end of each number.
- Complex numbers are numbers involving both real and imaginary numbers; thus, this question wouldn't make much sense without the imaginary number
The expression we are given is:
Open parenthesis and combine like terms:
This is answer choice B (assuming it's supposed to be an and not a "1" at the end)
Let me know if you need any clarifications, thanks!
~ Padoru
The product of this is 81
