3 years ago

A stray dog ate 30 muffins. That was 3/4 of all of them. How many did you start with?

1 answer:

6 0

For this equation the dog ate 3/4 of the 30 muffins. You would have started with 40 since the dog ate 3/4. So, the dog ate 3/4 muffins, and you would have 10 remaining.

Please let me know if this was right! Thanks!

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Alisa has a bunch of coins. She has pennies. She has nickels. She has dimes. She has quarters. They lie in one big pile. Alisa w

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Answer:

E. Not enough info.

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There could be 2 quarters 500 nickels and 7 pennies or 800 pennies 50 quarters and 2 nickels.

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JulsSmile [24]

Answer:

The width is 4

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2 years ago

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Maru [420]

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2 years ago

Someone please tell me how to solve this

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2 years ago

What is the value of B?

iragen [17]

$2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)$

$\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT$

<h3>Answer: B = 2</h3>

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3 years ago