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2 years ago

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A package of nine 12-ounce cans of cola costs $7.50. A half-gallon bottle of the same cola is sold for $2.90. Which cola has a c

heaper price, the cans or the bottle?

1 answer:

goldfiish [28.3K]2 years ago

6 0

Answer:

Cola bottles are cheaper. Mark me brainliest!

Step-by-step explanation:

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It represents equal parts of a whole or a collection?

Alina [70]

Answer:

Fraction

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve |x – 4| + 6 = 17.

const2013 [10]

Answer:

$\mathrm{C)\:}x=15,\:-7$

Step-by-step explanation:

For $|a-b|=c$ , there are two possible cases:

$\begin{cases}a-b=c\\a-b=-c\\\end{cases}$

Solving for both cases, we get:

$\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}$

6 0

2 years ago

What is the measure of angle Z?

Iteru [2.4K]

Answer:

sum of exterior angles of polygon = 360°

therefore,

z = 360 - (105+145)

z = 360 - 250

z = 110°

3 0

2 years ago

Jonathan uploaded some original songs and also some pictures. alissa uploaded four times as many songs, but only uploaded twice

lesya [120]

X is the number of songs and Y the number of pics

our 2 equations will be - X+y=11 & 4x+2y=24

consider x=11-y

Lets replace x in 2:

=4(11-y) +2y=24

=44-4y+2y=24

=44-24= 4y-2y

=20= 2y

=Y=20/2

=Y=10

Lets replace y in 1

=X+10=11

=X=11-10

=X=1

To learn more about equations from the given link

brainly.com/question/269374

#SPJ4

4 0

1 year ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago