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3 years ago

F(x) = -2x² – 12x – 19

Mathematics

1 answer:

Oliga [24]3 years ago

6 0

Answer:

just figue out 2x2 then the answer subtract 12x then subtrct 191

Step-by-step explanation:

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2. An elevator ascends, or goes up, at a rate of 750 feet per minute. Is the height

marshall27 [118]

Answer: yes I believe it is

Step-by-step explanation:

because if it were to go up 750 every minute then it would have to be proportional. :)

6 0

3 years ago

Read 2 more answers

Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.

Sladkaya [172]

Answer:

The solution is $\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

Step-by-step explanation:

From the question

The function given is $f(x) = \frac{e^{2x}}{ 25 + e^{4x}} dx$

The indefinite integral is mathematically represented as

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx$

Now let $e^{2x} = u$

=> $\frac{du}{dx} 2e^{2x}$

=> $2 e^{2x}dx = du$

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx = \int\limits {\frac{1}{ 2(25 + u^2)} } \, du$

$= \frac{1}{2} \int\limits {\frac{1}{ 25 + u^2)} } \, du$

$= \frac{1}{2} \int\limits {\frac{1}{ 5^2 + u^2)} } \, du$

$= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5} + C$

Now substituting for u

$\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

3 0

3 years ago

Please help with my geometry

erma4kov [3.2K]

25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
Sin^-1 = 14/25 = 34.0557
Round to hundreds
Solution: 34.06

8 0

3 years ago

19 - (- 41)<br> plzzzzzz help fast!

leonid [27]

Answer:

Step-by-step explanation:

Is because when you have two negative -- signs it became positive

19 + 41 = 60

3 0

3 years ago

Read 2 more answers

For the function f(x)=5x2−5x, evaluate and simplify.

Marianna [84]

9514 1404 393

Answer:

10x -5 +5h

Step-by-step explanation:

Use the function definition with the given arguments.

$\dfrac{f(x+h)-f(x)}{h}=\dfrac{(5(x+h)^2-5(x+h))-(5x^2-5x)}{h}\\\\=\dfrac{(5(x^2+2hx+h^2)-5(x+h))-(5x^2-5x)}{h}\\\\=\dfrac{5x^2+10hx+5h^2-5x-5h-5x^2+5x}{h}=\dfrac{10hx-5h+5h^2}{h}\\\\=\boxed{10x-5+5h}$

7 0

3 years ago