Answer:
1
Step-by-step explanation:
Using the definition
n
= 
where n! = n(n - 1)(n - 2) × 3 × 2 × 1
and 0! = 1
3
=
= 
=
= 1
Use a calculator called symbolab.com
Answer:
11<em>i</em>
Step-by-step explanation:
first you have to get a postive root.

then you solve the square roots from there, keeping in mind the imaginary number answer to the square root of -1, <em>i</em>.

Answer:
(7×x)+14
Step-by-step explanation: Because we have 14 added to something, we will need a + to whatever we are adding to. The product of 7 and a number is 7×x because product is the number you get after multiplication. So we get 7×x+14. You dont need parenthesis
Hope this helps!