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Andrews [41]
3 years ago
13

9u²v and which term are like terms?

Mathematics
2 answers:
madam [21]3 years ago
8 0
Answer: Since you didn't complete the problem, I can only give you some advice on how to pick the correct answer.

For terms to be like, they must contain the same variables. Also, the variables must be raised to the same power.

Look for another term that includes the exact variables: u^2v
NARA [144]3 years ago
8 0
I attached a diagram with the complete expression.

Answer:
5vu² is like 9u²v

Explanation:
Like terms are terms having the same degree for all variable it contains

The given term has two variables:
u² and v
This means that the term that is considered to be like this one should also have the variables u² and v.

Taking a look at the given terms, we would find that the only term satisfying this condition is 5vu².

Hope this helps :)

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7.For tire size P225/45R17, give the following: Width(mm): _______________ Aspect Ratio (%): _______________ Height (in.): _____
irakobra [83]

The width is the first numbers.

Width = 225 mm

Aspect ratio is the second number.

Aspect ratio is 45

Aspect ratio is width / height.

You have the ratio and width so you can calculate the height:

Multiply the width by the ratio:

Height = 225 x 0.45 = 101.25 mm

101.25/25.4 = 3.98 inches

The rim

Diameter is the last number

Rim diameter = 17 inches

So the overall height would be approximately 17 + 3.98 + 3.98 = 24.96 inches

Round the answers as needed.

3 0
3 years ago
HELP PLZ . Enter the slope of the line .
Korolek [52]
I hope this helps you



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4 0
3 years ago
Read 2 more answers
Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length
Bezzdna [24]

Answer:

Area of ΔDEF is 45\ cm^2.

Step-by-step explanation:

Given;

ΔABC and  ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = 2\ cm and

Length of DE = 6\ cm

Area of ΔABC = 5\ cm^2

Solution,

Since, ΔABC and  ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}

Where triangle 1 and triangle 2 is  ΔABC and  ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2

Thus the area of  ΔDEF is 45\ cm^2.

4 0
3 years ago
Read 2 more answers
la base de un rectángulo es es de 6 centímetros de largo y el area del rectángulo es de 91 centímetros cual es el perímetro​
HACTEHA [7]
Explanacio'n perdiccio'n
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7 0
3 years ago
Can someone help me with this one
rewona [7]
4 over 5 or y=4/5x+0
5 0
3 years ago
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