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andrezito [222]
3 years ago
9

Write the following numbers in standard form Thirteen thousand , eight , hundred forty three ,

Mathematics
2 answers:
Serga [27]3 years ago
6 0

Answer:

13,843

Step-by-step explanation:

bezimeni [28]3 years ago
6 0

13,843 Hope this helps

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         12x - 5y = 2
12x - 12x - 5y = -12x + 2
                 -5y = -12x + 2
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                    y = 2.4x - 0.4
               y - 3 = 2.4(x - 3)
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3 years ago
77/99 as a fraction or mixed number in simplest form
11111nata11111 [884]
If you divide both by 11, you get 7/9. 7/9 is the fraction in simplest form. 
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3 years ago
Which function does the graph represent?<br> (click on picture)
Crank

Answer:

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Step-by-step explanation:

7 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
Vera_Pavlovna [14]
B. 0.75 is the answer for this equation
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Question
Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) =  (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

          25 ft =  (1/2)*(32.17 ft/s^2)*t^2

         2*25ft = (32.17 ft/s^2)*t^2

           50ft =  (32.17 ft/s^2)*t^2

         √( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0
3 years ago
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