9514 1404 393
Answer:
(a) 6² +3² +1² +1² = 47
(b) 5² +4² +2² +1² +1² = 47
(c) 3³ +4² +2² = 47
Step-by-step explanation:
It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.
The approach where a cube is required can work the same way.
(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1
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(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...
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(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2
Answer:
b
Step-by-step explanation:
you can see in the figure, the function decrease from -1 to +3
Answer:
, for 
Step-by-step explanation:
The general form of quintic-order polynomial is:
According to the statement of the problem, the polynomial has the following roots:
Then, some algebraic handling is done to expand the polynomial:
If , then:
The answer to this problem is C.
Here's why:
The area of a triangle = 1/2 * (base) * (height) (Note: a triangle is half of a rectangle, and rectangles have Area = (base) * (height))
<span>Because the base of ΔAED is half of ΔACB (2 = (1/2) * 4), and height of ΔAED is half of ΔACB (3 = (1/2) * 6), we know that the area of ΔAED will be half of ΔAED.
</span>
So, it's C. I am sure =)
If it helped you, please mark me brainliest! =D
Have a nice day!
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