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3 years ago

Find the Number in Each Case

1 answer:

6 0

It seems like you have the answer already. but heres how its calculated.
$\frac{100}{15} = \frac{?}{3}$
so the missing number is 20 **cross multiply 100 and 3 to get 300 then divide 15 into 300 to get 20**

$\frac{160}{100} = \frac{80}{?}$
so the missing number is 50
**cross multiply 100 and 80 to get 8000 then divide 160<span> into 8000 to get 50**</span>

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HELP ASAP (Geometry)

Andrei [34K]

1) Parallel line: $y=-2x-3$

2) Rectangle

3) Perpendicular line: $y = 0.5x + 2.5$

4) x-coordinate: 2.7

5) Distance: $d=\sqrt{(4-3)^2+(7-1)^2}$

6) 3/8

7) Perimeter: 12.4 units

8) Area: 8 square units

9) Two slopes of triangle ABC are opposite reciprocals

10) Perpendicular line: $y-5=-4(x-(-1))$

Step-by-step explanation:

The equation of a line is in the form

$y=mx+q$

where m is the slope and q is the y-intercept.

Two lines are parallel to each other if they have same slope m.

The line given in this problem is

$y=-2x+7$

So its slope is $m=-2$ . Therefore, the only line parallel to this one is the line which have the same slope, which is:

$y=-2x-3$

Since it also has $m=-2$

We can verify that this is a rectangle by checking that the two diagonals are congruent. We have:

- First diagonal: $d_1 = \sqrt{(-3-(-1))^2+(4-(-2))^2}=\sqrt{(-2)^2+(6)^2}=6.32$

- Second diagonal: $d_2 = \sqrt{(1-(-5))^2+(0-2)^2}=\sqrt{6^2+(-2)^2}=6.32$

The diagonals are congruent, so this is a rectangle.

Given points A (0,1) and B (-2,5), the slope of the line is:

$m=\frac{5-1}{-2-0}=-2$

The slope of a line perpendicular to AB is equal to the inverse reciprocal of the slope of AB, so:

$m'=\frac{1}{2}$

And using the slope-intercept for,

$y-y_0 = m(x-x_0)$

Using the point $(x_0,y_0)=(7,1)$ we find:

$y-1=\frac{1}{2}(x-7)$

And re-arranging,

$y-1 = \frac{1}{2}x-\frac{7}{2}\\y=\frac{1}{2}x-\frac{5}{2}\\y=0.5x-2.5$

The endpoints of the segment are X(1,2) and Y(6,7).

We have to divide the sgment into 1/3 and 2/3 parts from X to Y, so for the x-coordinate we get:

$x' = x_0 + \frac{1}{3}(x_1 - x_0) = 1+\frac{1}{3}(6-1)=2.7$

The distance between two points $A(x_A,y_A)$ and $B(x_B,y_B)$ is given by

$d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

In this problem, the two points are

E(3,1)

F(4,7)

So the distance is given by

$d=\sqrt{(4-3)^2+(7-1)^2}$

We have:

A(3,4)

B(11,3)

Point C divides the segment into two parts with 3:5 ratio.

The distance between the x-coordinates of A and B is 8 units: this means that the x-coordinate of C falls 3 units to the right of the x-coordinate of A and 5 units to the left of the x-coordinate of B, so overall, the x-coordinate of C falls at

$\frac{3}{3+5}=\frac{3}{8}$

of the distance between A and B.

To find the perimeter, we have to calculate the length of each side:

$d_{EF}=\sqrt{(x_E-x_F)^2+(y_E-y_F)^2}=\sqrt{(-1-2)^2+(6-4)^2}=3.6$

$d_{FG}=\sqrt{(x_G-x_F)^2+(y_G-y_F)^2}=\sqrt{(-1-2)^2+(3-4)^2}=3.2$

$d_{GH}=\sqrt{(x_G-x_H)^2+(y_G-y_H)^2}=\sqrt{(-1-(-3))^2+(3-3)^2}=2$

$d_{EH}=\sqrt{(x_E-x_H)^2+(y_E-y_H)^2}=\sqrt{(-1-(-3))^2+(6-3)^2}=3.6$

So the perimeter is

p = 3.6 + 3.2 + 2 + 3.6 = 12.4

The area of a triangle is

$A=\frac{1}{2}(base)(height)$

For this triangle,

Base = XW

Height = YZ

We calculate the length of the base and of the height:

$Base =XW=\sqrt{(x_X-x_W)^2+(y_X-y_W)^2}=\sqrt{(6-2)^2+(3-(-1))^2}=5.7$

$Height =YZ=\sqrt{(x_Y-x_Z)^2+(y_Y-y_Z)^2}=\sqrt{(7-5)^2+(0-2)^2}=2.8$

So the area is

$A=\frac{1}{2}(XW)(YZ)=\frac{1}{2}(5.7)(2.8)=8$

A triangle is a right triangle when there is one right angle. This means that two sides of the triangle are perpendicular to each other: however, two lines are perpendicular when their slopes are opposite reciprocals. Therefore, this means that the true statement is

"Two slopes of triangle ABC are opposite reciprocals"

10)

The initial line is

$y=\frac{1}{4}x-6$

A line perpendicular to this one must have a slope which is the opposite reciprocal, so

$m'=-4$

Using the slope-intercept form,

$y-y_0 = m'(x-x_0)$

And using the point

$(x_0,y_0)=(-1,5)$

we find:

$y-5=-4(x-(-1))$

Learn more about parallel and perpendicular lines:

brainly.com/question/3414323

brainly.com/question/3569195

#LearnwithBrainly

8 0

3 years ago

I need help with 5-11

Damm [24]

Step-by-step explanation:

in an equilateral triangle all 3 sides are equally long. but that also means that all 3 angles are equal. and as the sum of all angles in a triangle has to be 180°, that means that each of the 3 Angie's is 180/3 = 60°.

so, KML = 60°.

HMK = 50°, KML = 60°.

all angles around M on one side of the line LG must have 180° in total too.

so,

HMG = 180 - 50 - 60 = 70°

since GHM is isoceles (GH and MH are equal), it means also that the angles at M and at G must be equal.

HMG = 70°

therefore, HGM = 70°

again, the sum of all angles in a triangle must be 180°, so

GHM = 180 - 70 - 70 = 40°.

again, in an isoceles triangle also the 2 "bottom" angles are equal. and together with the 180 sum rule we get

MHJ = (180 - 145)/2 = 35/2 = 17.5°.

if now the angle at G is 67°, then again, the angle at M must be equal (67°). and then again based on the 180 rule we get

GHM = 180 - 67 - 67 = 46°.

10.

since the 2 angles "at the bottom" are equal, it means ADE is an isoceles triangle.

since BC is parallel to DE, it means that ADE and ABC are similar triangles. and that means the corresponding angles are the same. and that means that the angles 3 and 4 are equal, and therefore ABC is an isoceles triangle. and that means that both legs AB and AC are equal.

11.

again, in an isoceles triangle the 2 base angles are equal. and together with the usual 180 rule that means

base angle = (180 - 18)/2 = 162/2 = 81°.

3 0

2 years ago

Analyze tables use the table that shows the percents of blood types of 145 donors during a recent blood drive

Alenkinab [10]

Answer:

a. 16

b. 80

c. Blood type AB

Step-by-step explanation:

Given:

O = 45%

A = 40%

B = 11%

AB = 4%

Total number of donors = 145

a. No. of donors that had type B blood = $\frac{11}{100}*145 = \frac{1,595}{100} = 15.95$

Type B blood donors ≈ 16

b. No. of blood donors without blood type O = $\frac{40 + 11 + 4}{100}*145 = \frac{55}{100}*145 = \frac{7,975}{100} = 79.75$

Those without blood type O ≈ 80

c. Find the number of people that had type AB:

Type AB = $\frac{4}{100}*145 = 5.8$ ≈ 6. This is less than 10 donors.

Therefore, blood type AB had less than 10 donors.

6 0

3 years ago

Please HELP I will give Brainliest!

ankoles [38]

The answer is the first page, first graph

5 0

3 years ago

I need help on my math!!!!!!!

AURORKA [14]

Answer:

Step-by-step explanation:

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4 0

3 years ago