Answer:
![d=7.07](https://tex.z-dn.net/?f=d%3D7.07)
Step-by-step explanation:
Distance Formula: ![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:
![d=\sqrt{(3-(-2))^2+(-4-1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%283-%28-2%29%29%5E2%2B%28-4-1%29%5E2%7D)
![d=\sqrt{(3+2)^2+(-5)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%283%2B2%29%5E2%2B%28-5%29%5E2%7D)
![d=\sqrt{(5)^2+25}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285%29%5E2%2B25%7D)
![d=\sqrt{25+25}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B25%2B25%7D)
![d=\sqrt{50}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B50%7D)
![d=5\sqrt{2}](https://tex.z-dn.net/?f=d%3D5%5Csqrt%7B2%7D)
![d=7.07](https://tex.z-dn.net/?f=d%3D7.07)
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer: Paul will be 30 years old
Step-by-step explanation:Let the age of her sister be x, then from the given data
=> 4x = 20
=> x = 5 years
The age of her sister is 5 years
In the second case, paul is twice as old as his sister
=> Age of paul = 2(x)
=> Age of paul = 10 years
Paul will be 10 years old when he is twice as old as his sister
Answer:
17 people per hour
Step-by-step explanation:
85/5
You would start out with multiplying giving you 5(x+6). then you would have a product of 5x+30. hoped this helped!