Answer:
the probability that at the end, at least 5 people stayed the entire time = 0.352
Step-by-step explanation:
From the question, 3 of the people are sure to stay the whole time. So, we'll deduct 3 from 6.which leaves us with 3 that are only 2/5 or 0.4 sure that they will stay the whole time.
Thus, what we need to compute to fulfill the probability that at the end, at least 5 people stayed the entire time of which we know 3 will stay, so for the remaining 3,we'll compute;
P[≥2] which is x~bin(3,0.4)
Thus;
P(≥2) = (C(3,2) x 0.4² x 0.6) + (C(3,3) x 0.4³)
P(≥2) = 0.288 + 0.064
P(≥2) = 0.352
The scale factor is 4 and for the perimeter just use the distance formula
Answer:
c = 5
Step-by-step explanation:
IT'S THE THREE FOUR FIVE TRIANGLE!!
3^2 + 4^2 = c^2
√25 = c
c = 5
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
