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cestrela7 [59]
4 years ago
5

You roll two six sided number cubes (dice). What is the BEST answer for the probability that the numbers rolled add to a number

greater than twelve?
Mathematics
2 answers:
rodikova [14]4 years ago
8 0
The highest number on dice is 6, so nothing can be higher than 12 when you roll 2 of them...

0/0

*Brainliest Please ♡´・ᴗ・`♡
Alexxx [7]4 years ago
7 0

Answer:

IMPOSSIBLE

Step-by-step explanation:

Impossible

The greatest possible roll is a 6 and 6 which equals 12, so there is zero percent chance of a number greater than 12.

0

12

= 0

The probability of an event occurring is somewhere between impossible (0) and certain (1.0).

-- Impossible is zero

-- Unlikely is close to zero

-- Very likely is close to one

-- Certain is one.

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Select the assumption necessary to start an indirect proof of the statement. If 3a+7 < 28, then a<7.
pashok25 [27]
When applying indirect proofs, we assume the negation of the conclusion is true, and show that this assumption would lead to nonsense, or contradiction.

In our case we assume a is not smaller than 7, that is we assume a≥7.

a≥7 then, multiplying both sides by 3:
3a≥21, then, adding both sides 7:

3a+7≥28,

which is a contradiction because 3a+7 is smaller than 28.

So our assumption is wrong, which means the opposite of it is correct.


Answer: assume a≥7
7 0
3 years ago
Can someone please help with this it’s worth 19 points?
nexus9112 [7]

Answer:

54, 36

Step-by-step explanation:

67+59+x=60*3

126+x=180

x=54

54 cones on Sunday

_____________________________________

180+x=54*4

180+x=216

x=36

36 cones on Monday

6 0
3 years ago
Write 2.4 x 10 to the power of -3 in standard form
fomenos

Answer:

Step-by-step explanation:

2.4 \times10^{-3}=\frac{24}{10} \times \frac{1}{10^3} =\frac{24}{10^4} =\frac{24}{10000} =0.0024

6 0
3 years ago
Solve the following equation algebraically<br>4x^2 = 100​
Licemer1 [7]

Answer:

x  = ±5

Step-by-step explanation:

4x^2 = 100​

Divide each side by 4

4/4x^2 = 100/4

x^2 = 25

Take the square root of each side

​sqrt(x^2) = ±sqrt(25)

x  = ±5

7 0
3 years ago
How many numbers between 100 and 999 are divisible by 4?
QveST [7]
Try this solution:
1. Note, that 100 is divisible by 4, and 999 is not divisible by it, only 996. This is an arithmetic sequence.
2. a1;a2;a3;a4;...a(n) the sequence, where a1=100; a2=104; a3=108; a4=112; ... etc., and a(n)=996. n=?
3. using a formula for n-term of the sequence: a(n)=a1+d(n-1), where a(n)=996; a1=100 and d=4 (according to the condition ' is divisible by 4'). Then 100+4(n-1)=996; ⇒ 4n=900; ⇒ n=225 (including 100).

answer: 225
7 0
3 years ago
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