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dmitriy555 [2]
3 years ago
12

There are 18 girls on a softball team

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

Option B)

Divide 18 by 6 and then multiply that quotient by 5

Step-by-step explanation:

We are given the following in the question:

Total number of girls in softball team = 18

Number of girls that are right handed =

=\dfrac{5}{6}\text{(Total number of girls)}

Number of right handed batters are:

=\dfrac{5}{6}\times 18\\\\=\dfrac{18}{6}\times 5\\\\=3\times 5\\=15

Thus, the correct answer is:

Option B)

Divide 18 by 6 and then multiply that quotient by 5

sineoko [7]3 years ago
5 0

Traductor de español

<h3 /><h3 /><h3>Respuesta: B. Divide 18 entre 6 y luego multiplica ese cociente por 5</h3><h3 /><h3>Explicar | Motivo: La razón de esta afirmación es que cuando la divide le da poder al diagrama que se encuentra arriba de esta afirmación.</h3><h3 /><h3>Si quieres que te explique más, házmelo saber :)</h3>

_________________________

English Translator

Answer: B. Divide 18 by 6 and then multiply that quotient by 5

Explain | Reason: The reason to this statement is that when you divide it gives power for the diagram above this statement.

If you want me to explain more please let me know :)

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24 x 4 tons and 2 pounds is:

96.02400 short tons

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3 years ago
six times jason collection of books and one third of nathan collection add up to 134 books. one third of jason collection and na
raketka [301]

Answer:

j = 21 and n = 14

Step-by-step explanation:

we have the equations:

6j + n/3 = 134

j/3 + n = 31

54j + 3n = 1206

j + 3n = 93

53j = 1113

j = 21

(21)/3 + n = 31

7 + n = 31

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3 years ago
Write an equation, and solve. Round your answer to the nearest cent.
VashaNatasha [74]

Answer:

The cost of 16 oz of granola should be $16.16

Step-by-step explanation:

Given that,

The cost of 3 oz of granola is $3.03

We need to find the cost of 16 oz of granola..

As 3 oz = $3.03

1 oz = (3.03/3) = $1.01

The cost of 16 oz will be :

16 oz = 16×1.01

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3 0
3 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

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22 because you take the smallest and largest number and subtract them so you do 81-59=22
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