What is the value of this expression 0.9[1/2-2]+0.6
1 answer:
You might be interested in
Answer:
p = -
Step-by-step explanation:
Given
p = ( factorise numerator and denominator )
x² - y² ← is a difference of squares and factors as (x - y)(x + y)
x² + xy ← factor out x from each term
= x(x + y) , thus
p = ← cancel (x + y) on numerator/ denominator
= ← substitute x = - 4, y = - 6
=
=
= = -
Answer:
Step-by-step explanation:
Let the original fraction be
Then adding 1 to the numerator gives
=
( cross- multiply )
⇒ y = 5x + 5 → (1)
Subtracting 1 from the denominator gives
=
(cross- multiply )
y - 1 = 7x → (2)
Substitute y = 5x + 5 into (2)
5x + 5 - 1 = 7x ← subtract 5x from both sides
4 = 2x ⇒ x = 2
Substitute x = 2 into (1)
y = (5 × 2) + 5 = 10 + 5 = 15
Hence original fraction =