Answer:
a) 10 <u>factor</u><u> </u>of 50
b) 50 <u>factor</u> of 50
c) 150 <u>multiple</u><u> </u>of 50
d) 75 <u>neither factor nor multiple </u>of 50
Answer:
Answer explained below
Step-by-step explanation:
Let a be the working hours of plant A.
Let b be the working hours of plant H.
Let c be the working hours of plant M.
We have to minimize , Z = 60a + 92b + 140c
subject to constraint , 40a + 20b + 40c >=350
20a + 40b + 40c >=240
where a>=0 , b>=0 ,c>=0
So ,by solving this , a = 7.67 , b= 2.17 , c = 0
So ,working hours of plant A = 8 hrs
working hours of plant H = 3 hrs
working hours of plant M = 0 hrs
Answer:
Is there a picture?
Step-by-step explanation:
B is the answer
the formula is :
which r stands for radius
and h stands for height
the diameter is 16
so the radius is
hope you understand it
When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
To learn more about number visit: brainly.com/question/17429689
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