♥It says that he adds 12$ each week, and by the end of 3 weeks he had 60. Well if you do 12*3
And that =36.
But as you can see its not 60 so we have to find out how much money he had in there before.
He had 24$ in there before he started doing this.
You can find this by doing 36+x=60 and 36+24=60.
Now if you do 12*15
You get 180.
Now add the 24 dollars he already had in there.
180+24=204
He had 204$ at the end of wk.15
♥Hope this helps!♥
Answer:
36 runners finished the race.
Step-by-step explanation:
In the first half of the race, 1/4 of them dropped, so we need to calculate 1/4 of 80:
(1/4) * 80 = 80/4 = 20
If 20 runners dropped out, now we have 80 - 20 = 60 runners.
Then, in the second half, 2/5 of the remaining runners dropped out, so:
(2/5) * 60 = 2*60/5 = 120/5 = 24
If 24 runners dropped out, now we have 60 - 24 = 36 runners.
So, 36 runners finished the race.
I^5 + i^6 + i^7 + i^8
i^11 + i^15
i^26
therefore your answer is:
i^26
Answer:
Step-by-step explanation:
The catch here is to break up sqrt(6) into 2 parts that use primes to define sqrt(6)
sqrt(3)* sqrt(6)
sqrt(6) can be broken up into sqrt(2*3) which equals sqrt(2)*sqrt(3)
sqrt(3)*sqrt(2)(sqrt(3)
sqrt(3)*sqrt(3)*sqrt(2)
3*sqrt(2)
