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Nana76 [90]
3 years ago
10

How many different​ three-digit numbers can be formed using the digits 1 comma 2 comma 9 comma 6 comma 4 comma 3 comma and 8 wit

hout​ repetition? For​ example, 664 is not allowed.
Mathematics
1 answer:
lozanna [386]3 years ago
3 0

Answer:

129 468  

Step-by-step explanation:

I'm not sure if you're supposed to reuse the same numbers just in a different Three digit number. Or if you're supposed to use the number one time and one time only. But if not here's there's some numbers that you could use

He basically all You have to do Is take the numbers and turning them into three digit numbers Without repetition.

Hope this helps you!

Also it's saying that 664 is not allowed Because it they are reusing the six When there's no Extra six to use. So remind you not to use the same number twice!

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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on -3 and 2 with shading going in the
Andrei [34K]
We are given with the inequality |2x + 1| ≤ 5 and asked to solve the equation. In this case, we take first the positive side, that is 2x + 1 ≤ 5. this is equal to 2x ≤ 4 or x ≤ 2. For the negative side, the equality is -5 ≤ 2x + 1. This is equal to -6 ≤ 2x or -3 ≤ x. Hence the solution is  -3 ≤ x ≤ 2. The answer is B. closed dots on -3 and 2 with shading in between. The equal in <span>≤  means closed dots.</span>
6 0
3 years ago
Read 2 more answers
Find the value of x in the equation below.<br> 48 = 6x
Akimi4 [234]

Answer:

x=8

Step-by-step explanation:

This is a simple one-step algebraic equation. In algebra, to find x you must isolate the variable. To do this, use the property of equality. This property states that an equation is still true if you do the same thing to both sides. For example, the equation would still be true if you added 1 to both sides.

To isolate x divide both sides by 6. This equals 48/6 = 6x/6. Which simplifies to 8=x.

7 0
3 years ago
Question:
snow_tiger [21]

Answer:

A (first picture)

Step-by-step explanation:

Based on the picture, the lines are both perpendicular and the red line splits AB into two equal parts (bisects it), so it must represent the perpendicular bisector of AB.

5 0
3 years ago
Write a proof for the following
anastassius [24]

Answer:

What will help is labeling the diagram with the given info..A proof always ends with the statement you have to prove.

Step-by-step explanation:

STATEMENT..............REASON

1) ∠F≅∠C             1) Given

2) E is the midpoint of GD     2) Given

3) GE≅ED       3) If a point is a midpoint then 2 ≅ segments are formed

4) FE≅EC        4)   Same as 3

5)∠G≅∠D     5)  

6) FG≅CD       6)

I tried my best with step 5 and 6..but you know step 6 has to be the prove statement but i don't know what the reason would be. I hope i helped a bit though.

4 0
3 years ago
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