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sergiy2304 [10]
4 years ago
11

Simplify the expression: (1 − 5i)(3 + 7i). 38 + 8i −32 + 8i 38 − 8i −32 − 8i

Mathematics
1 answer:
photoshop1234 [79]4 years ago
3 0
Your answer is 38-8i because what you do is 1 times 3 and get 3 then 1 times 7i and get 7i then you do -5i times 3 and you get -15i then -5i times 7i and you get -35i2 and the square will cancel out the negative and make it 35 then add that to the 3 and you get 38 then take the -15i +7i and get -8 do your answer is 38-8i
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How to find mean score of 90
gavmur [86]
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5 0
3 years ago
A classmate simplified a rational expression below
lara31 [8.8K]
<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

\:1-2x-4=x^2-x-2

-2x-3=x^2-x-2\:\:

0=x^2-2x-2\:\:

0=\left(x-1\right)\left(x-1\right)

x=1

<u><em>Identifying the Main Error</em></u>

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)   ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u>

<u><em /></u>\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)<em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

x^2-2x-8=x^2-x-2

x^2-2x-8+8=x^2-x-2+8

x^2-2x=x^2-x+6

-x=6

\frac{-x}{-1}=\frac{6}{-1}

x=-6

3 0
3 years ago
12
Tamiku [17]

Answer:

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Step-by-step explanation:

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bogdanovich [222]

Answer:

ESTA iEsto es una pregunta española

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