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atroni [7]
3 years ago
8

It took Mary 15 seconds to walk 10 feet. How fast was she walking, in feet per second?

Mathematics
2 answers:
zepelin [54]3 years ago
6 0
15 divided by 10 should get you your answer.
CaHeK987 [17]3 years ago
5 0
The answer is 1.5

15 divided by 10 = 1.5
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The marked price of an article is Rs.2080. After allowing d% discount and levying
mash [69]

Answer:

13%

Step-by-step explanation:

<u>Given:</u>

  • MP = 2080
  • Discount = d%
  • VAT = (d-2)%
  • Cost = 1997.84

<u>Apply discount:</u>

  • 2080 - d% = 2080*(1 - 0.01d)

<u>Add VAT:</u>

  • 2080*(1 - 0.01d) + (d - 2)%
  • 2080*(1 - 0.01d) * (1 + (d -2)/100)
  • 2080*(1 - 0.01d) * (0.98 + 0.01d) = 1997.84
  • (1 - 0.01d)(0.98 + 0.01d) = 1997.84/2080
  • 0.98 + 0.01d - 0.0098d - 0.0001d² = 0.9605
  • - 0.0001d² + 0.0002d + 0.98- 0.9605 = 0
  • 0.0001d²- 0.0002d - 0.0195 = 0
  • d² - 2d + 195 = 0

<u>Solving the quadratic equation we get:</u>

  • d = 15

<u>Then</u>

  • VAT rate = 15 - 2 = 13%
7 0
3 years ago
Given: MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm Find: The midsegment of MNOK
Sergeu [11.5K]

Answer:

12 cm

Step-by-step explanation:

1. Consider right triangle MNK. In this triangle angle N is right and m∠M=60°, then m∠K=30°. Thus, this triangle is special 30°-60°-90° right triangle with legs MN and NK and hypotenuse MK=16 cm. The leg MN is opposite to the angle with measure of 30°, then this leg is half of the hypotenuse, MN=8 cm.

2. Consider right triangle MNH, where NH is the height of trapezoid drawn from the point N. In this triangle m∠M=60°, angle H is right, then m∠N=30°. Similarly, the leg MH is half of the hypotenuse MN, MH=4 cm.

3. Trapezoid MNOK is isosceles, because MN=OK=8 cm. This means that NO=MK-2MH=16-8=8 cm.

4. The midsegment of the trapezoid is

\dfrac{MK+NO}{2}=\dfrac{16+8}{2}=12\ cm.

4 0
2 years ago
Sebastian is at the market buying apples and oranges he buys 2 2/5 less apples and oranges if he buys three 1/4 kilograms of ora
Assoli18 [71]
Sebastian has 200. Bye
8 0
3 years ago
Read 2 more answers
On a map, a distance of 2 cm represents 15 km. What is the distance (in km) between two cities that are 11 cm apart on the map?
GenaCL600 [577]

Answer:

82.5 km

Step-by-step explanation:

Given:

\frac{2cm}{15km} =\frac{11cm}{?km}

Cross-multiply.

2x = 11(15)

Divide both sides by 2 and solve for x.

x = 82.5 km

Please mark as Brainliest! :)

6 0
3 years ago
45 is 0.9% of what number
RUDIKE [14]

Answer:

0.405

Step-by-step explanation

45 x 0.9%= 0.405

8 0
2 years ago
Read 2 more answers
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