P + s = 200......p = 200 - s
20p + 15s = 3400
20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold
p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
Answer:
Range: (-3,0,3,6,9)
Step-by-step explanation:
We need to evaluate each value in the domain of the function, so
f(-2)=3(-2)+3=-6+3=-3
f(-1)=3(-1)+3=-3+3=0
f(0)=3(0)+3=0+3=3
f(1)=3(1)+3=3+3=6
f(2)=3(2)+3=6+3=9
Answer:
not so sure though but I think thats the answer
