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3 years ago

12

The perimeter of the square at the right is 48 inches. What is the area of the square at the right? Explain how you found your a

nswer.

1 answer:

Masja [62]3 years ago

4 0

If you have an image attached, i cant see it. Maybe just repost the question again cause i reallu cant see the attached image

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Work backwards to solve

leva [86]

Answer: $14.93

Step-by-step explanation:

First, lets remove the shipping price: 51.65 - 3.50 = 48.15

Next, lets find the sales tax of the shirts: 48.15 x 0.07 = 3.37

Then, subtract that from the shirt price: 48.15 - 3.37 = 44.78

Finally, divide 44.78 by 3: 44.78 / 3 = 14.93!

8 0

3 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

If you write out the numbers from 1 through 40 (including 1 and 40), how many numbers have a "5" in them?

GaryK [48]

Answer:

4

Step-by-step explanation:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40

6 0

3 years ago

I can't figure out how to solve this problem when y = -12

Delicious77 [7]

ززسنسح٢٩٣تبنخيخثزثوث

6 0

3 years ago

Is 3/8 equivalent to 12/24

Ghella [55]

No because 3 x 4 = 12 and 8 x 4 ≠ 24

4 0

2 years ago