C. The distance between A and C
Because |-2| = 2
And if you tried all the choices only C gives the same answer
First of all, we need to find the slope of the given line, writing it in the 
form and reading the 
coefficient:
So, the slope is 
If a line with slope 
is perpendicular to a line with slope , the following relationship holds:
So, the slope of our line must satisfy
So, we need the equation of a line with slope 1 and passing through (4,7). Given the slope and a point 
of a given line, its equation is given by
So, if you plug your values, you have
Answer:
y=2e^(−x)cosx−e^(−x)sinx
Satisfies the equation
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
y = e^(-x)[2cosx - sinx]
Find y' and y" using product law
y' = -e^(-x)[2cosx - sinx] + e^(-x)[-2sinx - cosx]
y' = -e^(-x)[2cosx - sinx + 2sinx + cosx]
y' = -e^(-x)[3cosx + sinx]
y" = e^(-x)[3cosx + sinx] - e^(-x)[-3sinx + cosx]
y" = e^(-x)[3cosx - cosx + sinx + 3sinx]
y" = e^(-x)[2cosx + 4sinx]
y" + 2y' + 2y
e^(-x)[2cosx + 4sinx] - 2e^(-x)[3cosx + sinx] +2e^(-x)[2cosx - sinx]
e^(-x)[4sinx - 2sinx - 2sinx + 2cosx - 6 cosx + 4cosx]
= e^(-x) × 0
= 0
18,264,947,048,470
there ya go
