Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
Katelan has 9 friends as guests for a costume party. Katelan is elaborating carnival masks for them. So far , she has made 7 masks. How much more masks is Katelan left to do?
Answer: Katelan has 2 masks left to do . Because 7 (plus) 2 is 9.
Answer:
$12,000,000
Step-by-step explanation:
The maximum will be the vertex and because this is written in vertex form the vertex will be (5, 12) so the maximum income will be 12 million dollars.
Answer:
The measure of segment AC is 36 units
Step-by-step explanation:
- The mid-point divides the segment into two equal parts in length
- B is the mid point of segment AC
- That means B divides segment AC into two equal parts in length
∴ AB = BC
∵ AC = 5x - 9
∵ AB = 2x
- The two parts AB and BC are equal in length
∴ BC = 2x
∵ AC = AB + BC
- Substitute the values of AB and BC in the expression of AC
∴ AC = 2x + 2x
∴ AC = 4x
∵ AC = 5x - 9
- Equate the two values of AC
∴ 5x - 9 = 4x
- Add 9 to both sides
∴ 5x = 4x + 9
- Subtract 4x from both sides
∴ x = 9
- Substitute the value of x in any expression of AC
∵ AC = 4x
∵ x = 9
∴ AC = 4(9) = 36
* The measure of segment AC is 36 units
Answer:
Step-by-step explanation:
∫tan(x)dx∫cot(x)dx∫sec(x)dx∫csc(x)dx====−ln∣∣cos(x)∣∣+C=ln∣∣sec(x)∣∣+Cln∣∣sin(x)∣∣+C=−ln∣∣csc(x)∣∣+Cln∣∣sec(x)+tan(x)∣∣+C−ln∣∣csc(x)+cot(x)∣∣+C
