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zvonat [6]
3 years ago
13

PLEASE HELP BEST ANSWER GETS BRANLIEST

Mathematics
2 answers:
BARSIC [14]3 years ago
5 0
C. The distance between A and C
Because |-2| = 2
And if you tried all the choices only C gives the same answer
professor190 [17]3 years ago
5 0
Hello!

I believe the best way to describe |-2| is 'the distance between A and C'.

When a number is in between two lines like this ( |-2| ), it means to find the absolute value of that number. Most people think the absolute value means it's the opposite of the number, but the absolute value is really the distance from 0. So the absolute value of 7 would be 7, because 7 is the distance the number is from 0. So |-2| would be described as the distance form Point A to Point C because its distance is two numbers away from 0.

I hope this helps!
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Answer:

y = 5.2

Step-by-step explanation:

x : y  =  5 : ?

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So,

<u><em>Condition:</em></u>

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Which image of the following scatterplots would have a trend line with a negative slope?
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The second image where the first row is x-1 y-4.5. The points go further towards the bottom from left to right, unlike the others that point up.
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An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

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Time can't be in negative;

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8 0
4 years ago
"A passenger train traveled 100 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the fre
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Answer: the rate of the passenger train is 100 mph.

Step-by-step explanation:

Let x represent the rate of the passenger train.

The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. It means that the rate of the freight train is (x - 10) mph

The passenger train traveled 100 miles. It means that the time it took travel 100 miles is

100/x

In the same amount of time, it took a freight train to travel 90 miles. It means that the time it took travel 90 miles is

90/(x - 10)

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100/x = 90/(x - 10)

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7 0
4 years ago
A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T
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Answer:

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :  

Null hypothesis:\mu \leq 75  

Alternative hypothesis:\mu > 75  

A. One-Tailed

z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189  

p_v =P(z>2.189)=0.0143  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Data given and notation  

We have the following data: 84 94 80 88 77 68 90 74 96 71

We can calculate the sample mean with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X=82.2 represent the sample mean  

\sigma=10.4 represent the population standard deviation  

n=10 sample size  

\mu_o =75 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :  

Null hypothesis:\mu \leq 75  

Alternative hypothesis:\mu > 75  

A. One-Tailed

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189  

P-value  

Since is a ONE-TAILED  test the p value would given by:  

p_v =P(z>2.189)=0.0143  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

5 0
3 years ago
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