Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and
Therefore segment NO is parallel to the segment KL.
Step-by-step explanation:
1. Ampltiude is 1
The period is
is the period
The phase shift is 0
2. The Ampltiude is 2
The period is 2 pi
The phase shift is 1
3. The amplitude is 3
The period is 2 pi/3
The phase shift is -2
4.The amplitude is 2/3
The period is -10pi
The phase shift is 0
5. The Ampltiude is 1
The period is -2 pi
The phase shift is pi
6. The amplitude is 1/4
The period is -4pi
The phase shift is negative 2pi/3
7. The Ampltiude is 3
The period is 4
The phase shift is 8
