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Alekssandra [29.7K]

3 years ago

12

A triangle has two sides that measure 4.56 cm and 8.65 cm. Which could be the measure of the third side?

1 answer:

sertanlavr [38]3 years ago

6 0

To test for a triangle, the two smallest sides added together have to be greater than the third side.

3.95 + 4.56 > 8.65
8.51 > 8.65
this is false

4.56 + 8.65 > 10.31
13.21 > 10.31
could be it

4.56 + 8.65 > 13.21
13.21 > 13.21
no, this would mean they're equal

4.56 + 8.65 > 20.25
13.21 > 20.25
this is also false

<span>B. 10.31 cm
</span>

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What is the answer 9 divide 5/8

siniylev [52]

9 ÷ (5/8)

9 multiplied by the reciprocal of 5/8 which is 8/5

9 * (8/5)

72/5 (ANSWER)

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3 years ago

For f(x) = 3x + 1 and g(x) = x2 - 6, find (f + g)(x).

alexdok [17]

(3x + 1) + (x2 - 6)
x2 + 3x - 5

8 0

3 years ago

The Murphy family is on a road trip. On the first day, they traveled 30% of their total distance. On the second day, they travel

Otrada [13]

Answer:

5/12

Step-by-step explanation:

Total distance travelled = 30% + 1/4

To add these numbers, convert 30% to fraction

30% = 1/3

1/3 + 1/4 = 7/12

Remaining distance = 1 - 7/12 = 5/12

7 0

3 years ago

Write an equation. Let x be the unknown number<br> sixteen is 18 less than twice a number.

svlad2 [7]

Answer:

17

Step-by-step explanation:

Let the number be x

16 = 2x - 18

Add 18 to both sides

16+18 = 2x

2x = 34

Divide both sides by 2

x = 34/2

x = 17

I hope this was helpful, please mark as brainliest

7 0

3 years ago

A student solves the following equation and determines that the solution is −2. Is the student correct? Explain. 3 a + 2 − 6a a2

Ganezh [65]

For this case, we have the following equation (according to the comments):

$\frac{3}{a+2} - \frac{6a}{a^2-4} = \frac{1}{a-2}$

First, we factor the quadratic expression in the denominator:

$\frac{3}{a+2} - \frac{6a}{(a-2)(a+2)} = \frac{1}{a-2}$

Then, we multiply both sides of the equation by (a-2) (a + 2):

$\frac{3(a-2)(a+2)}{a+2} - \frac{6a(a-2)(a+2)}{(a-2)(a+2)} = \frac{(a-2)(a+2)}{a-2}$

Later, canceling similar terms we have:

$3(a-2) - 6a = a+2$

We do distributive property on the left side of the equation:

$3a-6-6a=a+2$

By grouping variables and constant terms we have:

$3a - 6a -a = 2+6$

Rewriting we have:

$-4a=8$

Finally, by clearing "a" we have:

$a=-\frac{8}{4} a=-2$

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

Answer:

the student correct, but the value of a= -2 is an extraneous solution

8 0

4 years ago

Read 2 more answers