Given:
The expression is:

To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,

[Using BODMAS]

In option B,

[Using BODMAS]

In option C,


In option D,

[Using BODMAS]

After the calculation, we have
and
.
Therefore, the correct options are B and D.
Part B: From part A, it is clear that

Therefore, the correct option is C.
Given:
The number is
.
To find:
The a+bi form of given number.
Solution:
We have,

It can be written as

![[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7Bab%7D%3D%5Csqrt%7Ba%7D%5Csqrt%7Bb%7D%5D)
![[\because \sqrt{-1}=i]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7B-1%7D%3Di%5D)

Here, real part is missing. So, it can be taken as 0.

So, a = 0 and
.
Therefore, the a+bi form of given number is
.
The answer would be=22.9n
Answer:
j=49
Step-by-step explanation: