The quicksort pivot is an arbitrary element within the collection that is being sorted. Using the pivot point, the collection of elements is partitioned into two smaller lists of elements. Using some logic, the smaller elements are placed left of the pivot point, and larger elements are placed to the right of the pivot point. Ideally, you would prefer you pivot point to be a median of your dataset to optimize the creation of the two sublists into a balanced state.

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8 0

3 years ago

A clock is reading 10:27:54.0 (hr:min:sec) when it is discovered to be 4 seconds fast. Explain why it is undesirable to set it b

lara31 [8.8K]

Answer:

(a)Applications Time Stamp Events

(b)S=0.5(W- $T_{skew}$ )+ $T_{skew}$ , where $T_{skew}$ ≤W≤ $T_{skew}$ +8.

Explanation:

Some applications assume that clocks always advance, so they could timestamp events under this assumption.

In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.

We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.

Let us denote the software clock with S.

Then, S=c(W- $T_{skew}$ )+ $T_{skew}$ where:

$T_{skew}$ =The current Time(10:27:54) and;

c is to be found.

We already know that S= $T_{skew}$ +4 when W= $T_{skew}$ +8,

So:

S=c(W- $T_{skew}$ )+ $T_{skew}$

$T_{skew}$ +4=c( $T_{skew}$ +8- $T_{skew}$ )+ $T_{skew}$

4=8c

c=0.5

We obtain the formula

S=0.5(W- $T_{skew}$ )+ $T_{skew}$ , where $T_{skew}$ ≤W≤ $T_{skew}$ +8.

4 0

3 years ago

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topjm [15]

Answer:

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7 0

3 years ago