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3 years ago

TCP is the protocol responsible for the delivery of data on the Internet, and IP provides addresses and routing information.

1 answer:

4 0

TCP is the protocol responsible for the delivery of data on the Internet, and IP provides addresses and routing information.
This is a true statement.

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What is output? Select all that apply. c = 0 while (c < 10): c = c + 5 print (c) 0 1 2 3 4 5 6 7 8 9 10

Harlamova29_29 [7]

Answer:

5 10

Explanation:

that's the answer : 5 10

4 0

3 years ago

Explain the steps in starting the MS Access from the Start Menu.

blondinia [14]

Explanation:

As with most windows programs Access can be executed by navigation the start menu in the lower left hand corner of the windows desktop. To Acess, click on the start button, then the programs menu then move to the Microsoft Office menu a.d finally click on the Microsoft Access menu item.

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3 years ago

A strategy to solve a logic problem is to break it into steps. Using the drop-down menu, complete these sentences about solving

PSYCHO15rus [73]

I think the answer is 3!!

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3 years ago

Read 2 more answers

How can you ensure that your web pages are compliant with a w3c standard?

miss Akunina [59]

Use a code validation tool.

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3 years ago

In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha

baherus [9]

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>

using namespace std;

bool getplayer2move(int x, int y, int n)

{

int dp[n + 1];

dp[0] = false;

dp[1] = true;

for (int i = 2; i <= n; i++) {

if (i - 1 >= 0 and !dp[i - 1])

dp[i] = true;

else if (i - x >= 0 and !dp[i - x])

dp[i] = true;

else if (i - y >= 0 and !dp[i - y])

dp[i] = true;

else

dp[i] = false;

}

return dp[n];

}

int main()

{

int x = 3, y = 4, n = 5;

if (findWinner(x, y, n))

cout << 'A';

else

cout << 'B';

return 0;

}

8 0

3 years ago