#include
#include
using namespace std;
int main(){
int input[] = {-19, 34, -54, 65, -1};
std::vector voutput:
std::vector vinput (input, input + sizeof(input) / sizeof(int) );
for (std::vector::iterator it = vinput.begin(); it != vinput.end(); ++it)
if(*it > 0) voutput.insert(voutput.begin(), *it);
for(std::vector::iterator it = voutput.begin(); it < voutput.end(); ++it)
std::cout << *it << ‘\n’ ;
return 0;
}
Answer: Dynamic packet filtering
Explanation:
Dynamic packet filtering is the type of fire wall which is used automatically to enabled the modification in the real time based on the traffic content according to the filtering rules.
The dynamic packet filtering also facilitates to monitor the actual state of connection which is active.
It is also used to determine the actual state of network packet and permits the packet of network pass through firewall.
The answer is depends. You can only get what the port lets you get. If the phone bans sending photos over Bluetooth than you can’t get the photos
Answer:
kkbvvvvvvvvvvvvvvvvv'vvvkk
Answer:
Hence the code is given as follows,
import java.util.Scanner;
public class LabProgram {
public static String createAcronym(String userPhrase){
String result = "";
String splits[] = userPhrase.split(" ");
for(int i = 0;i<splits.length;i++){
if(splits[i].charAt(0)>='A' && splits[i].charAt(0)<='Z')
result += splits[i].charAt(0);
}
return result;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
System.out.println(createAcronym(s));
}
}
