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egoroff_w [7]
3 years ago
10

A rectonale has an area of36cm and width 3cm. Find it's perimeter.​

Mathematics
2 answers:
belka [17]3 years ago
8 0
It is 29 hope this helps
Alex17521 [72]3 years ago
3 0

Answer:

\boxed{ \bold {\huge{ \text{30 \: cm}}}}

Step-by-step explanation:

\star{ \sf{ \underline{  \:  \: Given}}}

Area of a rectangle ( A ) = 36 cm²

Width of a rectangle ( w ) = 3 cm

\star{ \sf{ \underline{ \:  \: To \: Find}}} :

Perimeter of a rectangle ( P ) = ?

<u>First</u><u>,</u><u> </u><u>finding</u><u> </u><u>the </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>(</u><u> </u><u>l</u><u> </u><u>)</u><u> </u><u>:</u>

\boxed{\text{area \: of \: a \: rectangle = length ∗  width}}

\dashrightarrow{ \sf{36 = length \times 3}}

\dashrightarrow{ \sf{36 = 3 \: length}}

\dashrightarrow{ \sf{3 \: length = 36}}

\dashrightarrow{ \sf{ \frac{3 \: length}{3}  =  \frac{36}{3} }}

\dashrightarrow{ \sf{length = 12 \: cm}}

Length of a rectangle = 12 cm

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>perimeter </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>cm</u><u> </u><u>and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>3</u><u> </u><u>cm</u>

\boxed{ \text{perimeter \: of \: a \: rectangle = 2(l + w)}}

{ \sf{perimeter \: of \: a \: rectangle = 2(12 + 3)}}

\dashrightarrow{ \sf{perimeter \: of \: rectangle = 2 \times 15}}

\dashrightarrow{ \sf{perimeter \: of \: rectangle = 30 \: cm}}

Perimeter of a rectangle = 30 cm

Hope I helped!

Best regards! :D

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