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Luda [366]
2 years ago
5

The price of gallon of gasoline went from $3.50 to $2.87. What is the percent decrease?

Mathematics
2 answers:
Sveta_85 [38]2 years ago
7 0

Answer:

69%

Step-by-step explanation:

noname [10]2 years ago
7 0
SORRY I DONT KNOW SORRY SORRY
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A sociologist recently conducted a survey of senior citizens who have net worths too high to qualify for Medicaid but have no pr
hjlf

Answer:

a) s= 9.74

D. 9.74

b) Median= 74

B. 74

Step-by-step explanation:

Part a

We have the following dataset given:

69 74 75 62 70 93 64 69 61 88 67 77 87 90 66 91 77 63 82 82 71 74 76 65 83

We can begin calculating the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 75.04

Now we can calculate the sample deviation with the following formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}

And after replace we got:

s= 9.74

Part b

For this case we need to sort the value on increasing way:

[1] 61 62 63 64 65 66 67 69 69 70 71 74 74 75 76 77 77 82 82 83 87 88 90 91 93

And the median would be the value in the position 13 and we got:

Median= 74

6 0
3 years ago
The parallelogram shown below has an area of 35 units2.
sleet_krkn [62]
The height is 5 becuase if the area is 35 that means the length is 7 so you would divide and get 5
6 0
3 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
Help pls , will mark first answer brainliest. which graph represents the equation in the pictures?
Gekata [30.6K]

There is only one graph

8 0
3 years ago
Test each statement below to see if it is reversible. If so, write it as a true biconditional. If not, write not reversible
FinnZ [79.3K]
Statement: Complementary angles are two angles with measures that have a sum of 90.
Reverse: Two angles with measures that have a sum of 90 are complementary angles.

Here the reverse is true, therefore, the statement is true biconditional.

Statement: A rectangle is a four-sided figure with at least one right angle.
Reverse: A four sided figure with at least one right angle is a rectangle.

Here, the reverse is not true, therefore, the statement is not reversible.
3 0
3 years ago
Read 2 more answers
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