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Katyanochek1 [597]
3 years ago
7

56x700 :] just do your best

Mathematics
2 answers:
qwelly [4]3 years ago
6 0
39,200 will be the answer
Klio2033 [76]3 years ago
5 0

Answer:39,200

Step-by-step explanation: 56 time 700 is 39,00

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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
Consider the vector field.f(x, y, z) = xy2z2i + x2yz2j + x2y2zk(a) find the curl of the vector field.
Marysya12 [62]
First introduce the following notations:
P=yx^2z^2\\Q=x^2yz^2\\R=x^2y^2z\\\text{Then compute the partial derivative like this:}\\R_y=2x^2yz\\Q_z=2x^2yz\\P_z=2yx^2z\\R_x=2xy^2z\\Q_x=2xyz^2\\P_y=x^2z^2\\\text{Then evaluate each of the following:}\\R_y-Q_z=2x^2yz-2x^2yz=0\\P_z-R_x=2yx^2z-2xy^2z=2xyx(x-y)\\Q_x-R_y=2xyz^2-x^2z^2=z^2x(2y-x)\\\text{Our answer will be then:}\\Curl(f)=(2xyx(x-y))j+(z^2x(2y-x))k
7 0
3 years ago
If my equation was <br> 8x5+4x2+3x2<br> How would I write it with parenthesis?
Norma-Jean [14]
You re write the equation with parentheses as (8x5)+(4x2)+(3x2).
5 0
3 years ago
Read 2 more answers
Can someone help me? It's urgent and thank you!
Irina-Kira [14]

Answer:

option A

Step-by-step explanation:

\frac{x+ 3}{12x} \ \cdot \ \frac{4x}{x^2 +x - 6}\\\\= \frac{x+ 3}{12x} \ \cdot\ \frac{4x}{x^2 +3x - 2x - 6}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{x(x + 3) -2(x+3)}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{(x + 3)(x -2)}\\\\= \frac{1}{12x} \ \cdot \ \frac{4x}{(x - 2)} \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \  \\\\= \frac{1}{3} \ \cdot \ \frac{1}{(x - 2)}\\\\= \frac{1}{3(x - 2) }

5 0
3 years ago
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Sliva [168]
Your answer is D you’re welcome!
4 0
3 years ago
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