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ioda
3 years ago
9

A 7 kg ham costs $19/kg. Find the cost per pound.

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer: \$8.62/\text{Pound}

Step-by-step explanation:

Given

There is 7\ kg of ham available which costs

cost=\$\ 19/kg

i.e.

1\ kg\ \text{costs}\ \$19

and we know

1\ kg=2.204\ \text{pound}

So, 2.204\ \text{Pound costs}\ \$19

thus 1\ \text{Pound costs}\ \dfrac{19}{2.204}=\$8.62/\text{Pound}

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Y
Luba_88 [7]

Answer:

a

Step-by-step explanation:

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This statement is true

Hope this helps!

3 0
3 years ago
Points A and B on the coordinate grid below show the positions of two midfield players of a soccer team: Coordinate grid shown f
gavmur [86]

Answer:

Point B is the correct answer. For the best relationship between the positions of the two midfielders.

Step-by-step explanation:


4 0
3 years ago
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Which of the following phrases best summarizes Chapter 13 bankruptcy? a. discharge debt and keep property b. discharge debt and
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Answer:

c.

reorganize debt and keep property

5 0
3 years ago
A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is σ = 15. a. Compute the
Kaylis [27]

Answer:

a) (76.21,83.79)

b) (77.32,82.68)    

c) Interval decreases    

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 60

Sample mean = 80

Sample standard Deviation, s = 15

a) 95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

80 \pm 1.96(\dfrac{15}{\sqrt{60}} ) = 80 \pm 3.79 = (76.21,83.79)

b) Sample size, n = 120

95% Confidence interval:

80 \pm 1.96(\dfrac{15}{\sqrt{120}} ) = 80 \pm 2.68 = (77.32,82.68)

c) As observed increasing the sample size, the confidence interval become smaller.

8 0
3 years ago
The ratio of boys to girls is exactly the same in classes 701 and 702. Class 701 has 12 boys and 18 girls.
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Answer:

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Step-by-step explanation:

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3 years ago
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