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Mumz [18]
3 years ago
14

If AB = 10, AC = 6, and BC = 6, find AD:

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

If the figure is a rectangle ABCD then AB=10, BC=6, AC=6, THEN AD=AB(opposite sides of a rectangle are equal)

hence AD=10

HOPE IT HELPED....

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For a certain​ candy, 20​% of the pieces are​ yellow, 15​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a
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Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

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Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

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  • the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}

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\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}

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3 years ago
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