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Brilliant_brown [7]
3 years ago
7

Help me solve these please

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0
(4,5) just took test.
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Someone please explain I have zero clue how to answer this! ​
UkoKoshka [18]

Answer:

x=62

Step-by-step explanation:

152-90(because of the right angle)

the 28 is a red herring

4 0
3 years ago
Solve the system of equations using row operations. Write your answer in the form (x, y).
Sonja [21]

Answer:

(5, - 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = - 2 → (1)

3x - y = 19 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the y- term

9x - 3y = 57 → (3)

Add (1) and (3) term by term to eliminate y

(2x + 9x) + (3y - 3y) = (- 2 + 57), that is

11x = 55 ( divide both sides by 5 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

2(5) + 3y = - 2

10 + 3y = - 2 ( subtract 10 from both sides )

3y = - 12 ( divide both sides by 3 )

y = - 4

Solution is (5, - 4 )

8 0
3 years ago
Fraction that is less than 5\6 and has a denominator of 8
Debora [2.8K]
1/8 would be smaller
8 0
3 years ago
Mr. Hills horses, all together, eat 395 pounds of oats each month. If Mr. Hills has 5 horses, and each horse eats the sane amoun
Marizza181 [45]
I would say 80, because without an estimate it'd be 79 and 79x5=395. So 80x5=400, which is the estimate of 395. So 80 is the answer
8 0
3 years ago
Which of the following correctly describes the domain of the function shown
labwork [276]

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, \{x: x \neq 0\} is not the domain of the function.

Option B: \{x: x \neq \pm 1\}

Substitute x = –1 in r(x).

$r(-1)=\frac{2 \times (-1)}{-1-1}=1

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, \{x: x \neq \pm 1\} is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: \{x: x \neq 1\}

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

4 0
3 years ago
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