Answer:
1) After 2 years the value of the car decreases to $22,600.
2) d(0,-1) it just wouldn't be linear
3) a each number has one line drawn from and b just draw another letter going to more than one number
Step-by-step explanation:
If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182
The number of books that Pamela can shelf at a time = 26
The number of books that Debbie can shelf at a time = 7
If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is the least common multiple of 26 and 7
The Least common multiple of 26 and 7 = 182
Therefore, if both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182
Learn more on Least Common Multiple here: brainly.com/question/363238
Answer:
943,281
Step-by-step explanation:
Just move the 3 up a value
If it's in the ten's place, then move it to the hundred's place value.
If it's in the hundred's place, then move it to thousand's place value.
So on and so on...
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP
If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8
2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2
Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4
FC= 2/(1+2) * AC
FC= 2/3 * 12= 8
3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2
DC=3x+12= 3(-2) +12= 6
4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3
C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1
y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1
y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)
5.
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
