Answer:
D. d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
C. d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
B. d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Step-by-step explanation:
Given two points (x1, y1) and (x2,y2) we can find the distance using
d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
The order of the terms inside the square doesn't matter
d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
When we are squaring are term, we can take the absolute value before we square and it does not change the value
d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
Answer:
20pi or 62.83
Step-by-step explanation:
when r=4
pi r^2
16pi
when r=6
pi r^2
36pi
36pi-16pi=20pi or 62.83
It’s b. The second table.