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77julia77 [94]
4 years ago
12

In a wood there are 420 silver birch trees 160 oak trees and 300 wild cherry trees what percentage is the oak trees give answer

to 1 decimal place
Mathematics
2 answers:
frosja888 [35]4 years ago
6 0
That would be 7.2 if my calculations are correct
Yuliya22 [10]4 years ago
6 0

Answer: 18.2\%

Step-by-step explanation:

Given : The number of silver birch trees = 420

The number of oak trees = 160

The number of wild cherry trees =300

The total number of trees = 420+160+300=880

Now, the percentage of oak trees :-

\dfrac{\text{Number of oak trees}}{\text{Total trees}}\times100\\\\=\dfrac{160}{880}\times100=18.1818181818\approx18.2\%

Hence, the percentage of oak trees =18.2\%

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Answer:

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Step-by-step explanation:

hope this helps :)

7 0
2 years ago
The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. The helicopter flies for
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Answer: 44 gallons

Step-by-step explanation:

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Therefore the helicopter uses 44gallons for 4 hours.

3 0
3 years ago
What is the product of b(b^2 - 12b+1)
Strike441 [17]

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Step-by-step explanation:

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3 0
3 years ago
Pythagoras ' Theorem - Solving Complex Problems​
Snezhnost [94]

Answer:

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OP²=MO²-MP²

OP²=25²-7²

OP²=(25+7)(25-7)

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OP=√256

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2.draw a straight line from the angle C and name that line with CE

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7 0
2 years ago
Read 2 more answers
The body of a 154-pound person contains approximately milligrams of gold and milligrams of aluminum. based on this information,
Lady_Fox [76]

This question is incomplete

Complete Question

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

Answer:

300 times

Step-by-step explanation:

From the above question, we are told:

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

We create a proportion

2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum

= 0.2 mg of gold : 60 mg of aluminum

Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:

60mg ÷ 0.2 mg

= 300

Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body

8 0
4 years ago
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