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kotykmax [81]
2 years ago
11

Complete the explanation of the procedure that can be used to solve 5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55. Then solve the e

quation. Use the Distributive Property to distribute the 3 and 2 inside the square parentheses on the left side. Next, inside the square parentheses. Then to distribute 5. Combine like terms on the left side and to solve the equation. The solution is x = .
Mathematics
1 answer:
Debora [2.8K]2 years ago
8 0

Answer:

x =  2.

Step-by-step explanation:

5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55

5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55

5[5x + 10] - x - 15 = 14x + 55

25x + 50  - x - 15 = 14x + 55     Now we subtract 14x from both sides:

25x + 50  - x - 15  - 14x = 14x - 14x + 55

10x + 50 - 15 = 55 Now we subtract  50, add 15 to both sides:

10x + 50 - 50 - 15 + 15 = 55 - 50 + 15    

10x =  20

x = 2.

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2 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
A.Solve for x. Then, using that information, find the measure of
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Answer:

See answers below

Step-by-step explanation:

Since both trinagles asre similar hence the ratio of the similar sides are equal.

From both triangles;

y + 7 = 3y - 7

y - 3y = -7-7

-2y = -14

y = 14/2

y = 7

FE = 3y - 17

FE = 3(7) - 17

FE = 21 - 17

FE = 4

AB = y'+7

AB = 7 + 7

AB = 14

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3x+20 = 5x - 80

3x -5x = -80-20

-2x = -100

x = 100/2

x = 50

<A = 3x + 20

<A = 3(50) + 20

<A = 150 + 20

<A = 170degrees

Hence x= 50 and y = 7

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