Answer:
A quick hack is often to partially express some function in terms of a Taylor approximation about x0, since higher order terms of x go to zero if we are considering limits for (x−x0)→0. To really answer your question we need to know what the original question was, that is, about which point do you want the expansion? Let us assume around 0. Then we have the Maclaurin series:
cos(x)=1−12x2+O(x4)
You can add more terms if you need to. Now we write:
ln(1+(−12x2))=…
Do you know the standard Maclaurin series for this function?
Hint: it is of the form ln(1+u)
Step-by-step explanation:
Answer:
26 I think
Step-by-step explanation:
i don't really know but I think it's 26
9514 1404 393
Answer:
65.6%
Step-by-step explanation:
The question is essentially asking the ratio of the volumes.
Va = πr²h = π(15²)(20)
Vb = πr²h = π(19²)(19)
The ratio of volumes is ...
Va/Vb = π(15²)(20)/(π(19³)) = (15²)(20)/19³ ≈ 0.65607
Container B will be about 65.6% full when container A is empty.
Answer is: B) An allowable amount of variation of a specified quantity, especially in the dimensions of a machine part.
Tolerance is how much something can take.
You do -2 plus 4. Answer is 2.
Then do 2-(-2) which is 0.
The final answer is 2.
