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vfiekz [6]
3 years ago
8

X³+y³+z³=k If u get a right answer its going to be marked brainliest

Mathematics
1 answer:
scoray [572]3 years ago
5 0

Answer:

x3+y3+z3

Step-by-step explanation:

hope it helps

You might be interested in
Escribe el número que tenga el mismo valor que 28 decenas
adoni [48]

Answer:

280

Step-by-step explanation:

<u><em>The question in English is</em></u>

Write the number that has the same value as 28 tens

we know that

One tens is equal to the number 10

so

To find out the value of 28 tens, multiply the number 28 by 10

28(10)=280

6 0
2 years ago
In a sample of 400 voters, 360 indicated they favor the incumbent governor. The 95% confidence interval of voters not favoring t
sveticcg [70]

The 95% confidence interval of voters not favoring the incumbent is (0.0706, 0.1294).

Sample size, n=400

Sample proportion, p = 40 / 400

= 0.1

We use normal approximation, for this, we check that both np and n(1-p) >5.

Since n*p = 40 > 5 and n*(1-p) = 360 > 5, we can take binomial random variable as normally distributed, with mean = p = 0.1 and standard deviation  = root( p * (1-p) /n )

= 0.015

For constructing Confidence interval,

Margin of Error (ME) =  z x SD = 0.0294

95% confidence interval is given by Sample Mean +/- (Margin of Error)

0.1 +/- 0.0294 = (0.0706 , 0.1294)

Learn more about Margin of Error here brainly.com/question/15691460

#SPJ4

5 0
1 year ago
Juan rolls a number cube 40 times. He rolls a 3 on the number cube 6 times. What is the experimental probability that he rolls a
kupik [55]
The correct answer is A. 3/20
6 0
2 years ago
Explain how you can use base-ten blocks or as a decimal models to find 3.15 divided by 3. Include pictures to support your expla
blondinia [14]
With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes
3 0
2 years ago
What is the simplified form of the quantity y−squared minus y minus 12 over the quantity y−squared minus 2y minus 15?
makvit [3.9K]
(y^2-y-12)/(y^2-2y-15)  factor both the numerator and denominator...

(y^2-4y+3y-12)/(y^2-5y+3y-15)

(y(y-4)+3(y-4))/(y(y-5)+3(y-5))

((y-4)(y+3))/((y-5)(y+3))  so the (y+3) terms cancel leaving

(y-4)/(y-5)

6 0
2 years ago
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