Answer:
At most, Liam can only buy lunch for 6 people.
Step-by-step explanation:
It isn't going to be a decimal answer because there can't be half of a person
All you have to do is divide 50 by 8 and round down because you don't want to spend more than 50 dollars.
Writing it mathematically, it would be:
p 
6
Answer:
umm 6.0?
Step-by-step explanation:
Here is how you find the number of possible U.S Zip codes.
<span>Take note of this: There are 10 1 digit numbers: 0,1,2,3,4,5,6,7,8,9.
</span>And we have 5 slots. So in each slot, there can be 10 possible numbers.
So let's put 10 in each blank slot.
10, 10, 10, 10, 10.
Therefore, the final answer would be 100,000. There are 100,000 possibilities of different U.S zip codes. Hope this answer helps.
So start with the top one and end w the bottom
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
